6. What is the percent yield of a reaction that produces 9.8 g of CO when 25.0 g of Fe3O4 reacts with excess
carbon?
Fe3O4 + 4C - 3Fe + 4CO
Answers
Answered by
0
Given:
The mass of Fe3O4 taken = 25 gm
To Find:
The percentage yield of the reaction.
Calculation:
- According to the given reaction:
The mass of CO produced by 232 gm of Fe3O4 = 112 gm
⇒ The mass of CO produced by 25 gm of Fe3O4 = (112/232) × 25 gm
⇒ The mass of CO produced by 25 gm of Fe3O4 = 12.07 gm
⇒ Theoretical yield = 12.07 gm
- Percentage yield = (Actual yield/Theoretical yield) × 100
⇒ Percentage yield = (9.8/12.07) × 100
⇒ Percentage yield = 81.193 %
- So, the percentage yield of the reaction is 81.193%.
Similar questions