Question

6. What is the smallest number which when increased by 3, is fully divisible by 21, 25, 27

& 35.

a) 4735 b) 4635 c) 4725 d) 4722​

Answer 1

Answer:

Step-by-step explanation:

for this question, lets find the lcm of 21 25 and 27

21 = 3 x 7

25 = 5 x 5

27 = 3 x 3 x 3

LCM = 3 x 3 x 3 x 5 x 5 x 7

LCM = 27 x 25 x 7

LCM = 4725

now if the number be x, then according to question

x + 3 = 4725

x = 4722

option D

CHEERS MATE, PLEASE MARK BRAINLIEST

Answer 2

Answer:

option C) 4725 it is divisible by all 21,25,27&35