6. What number should be added to x²+ 5 so that the resulting polynomial
leaves the remainder 3 when divided by x + 3?
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Answer:
There are infinity solutions. If we add a polinomial f (x) for x^2 + 5, and g (x) is the quoitient. Then,
X^2+5+f (x) = (x+3)g (x) + 3
Sub x =-3
(-3)^2+5+f (-3)=0+3
9+5+f (-3)=3
f (-3)=-11
Therefore all functions such f (-3)=-11 can be added to x^2+5 to give a remainder 3 when divided by x+3.
If a integer need to be added that must be -11.
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