Question

6. What would be the mean and median of the following data?
1,0,2,3,0,2,3,4,0, 2,5​

Answer 1

Answer:

Arranging given marks in ascending order,

4,7,7,9,9,9,10,12,15

Number of observations (n)=9

⇒ Mean=

9

4+7+7+9+9+9+10+12+15

=

9

82

=9.11

⇒ Here, number 9 occurs maximum number of times i.e 3 times.

∴ Mode=9

Number of observation is odd number

∴ Median=(

2

n+1

)

th

obs=(

2

9+1

)

th

obs=5

th

obs

Here, 5

th

obs=9

∴ Median=9

⇒ So, we can see mean measure is maximum and mode,median measures are minimum.

Answer 2

Answer:

First arrange the Given data in ascending order :-

• 0,0,0,1,2,2,2,3,3,4,5

• Number of observation (n) = 11

$:\implies \sf Mean \: of \: Data = \dfrac{Sum \: of \: all \: observations}{Number \: of \: all \: observations}$

$:\implies \sf Mean \: of \: Data = \dfrac{0 + 0 + 0 + 1 + 2 + 2 + 2 + 3 + 3 + 4 + 5}{11}$

$:\implies \sf Mean \: of \: Data = \dfrac{22}{11}$

$:\implies \underline{ \boxed{\sf Mean \: of \: Data = 2}}$

_____________________...

$\sf => Median =\Bigg\lgroup\dfrac{n + 1}{ 2}\Bigg\rgroup^{th} \: observation$

$\sf => Median = \Bigg\lgroup\dfrac{11 + 1}{2}\Bigg\rgroup^{th} \: observation$

$\sf => Median = \bigg\lgroup\dfrac{12}{2}\bigg\rgroup^{th} \: observation$

$\sf => Median = 6^{th} \: observation$

$=> \underline{\boxed{ \sf Median = 2}}$