Question

6. When a 12 V battery is connected to a resistor, the current in it is a 0.4 A.
what is the resistance of a resistor? What would be the current through it
when it is connected to battery of 6 V?​

Answer 1

Answer:

hi

Potential Difference,V = 24 V

Potential Difference,V = 24 VCurrent,I = 0.4 A

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x R

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 V

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohm

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?V = I x R

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?V = I x R6 = I x 60 

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?V = I x R6 = I x 60 I = 6 / 60 A

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?V = I x R6 = I x 60 I = 6 / 60 A  = 1 / 10 A

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?V = I x R6 = I x 60 I = 6 / 60 A  = 1 / 10 AI =  0.1 A .

Potential Difference,V = 24 VCurrent,I = 0.4 AResistance,R = ?V = I x R24 = 0.4 x RR = 24 / 0.4R = 240 / 4R = 60 ohm.Potential Difference,V = 6 VResistance,R = 60 ohmCurrent,I = ?V = I x R6 = I x 60 I = 6 / 60 A  = 1 / 10 AI =  0.1 A .

Answer 2

Answer:

R=p.d./ current

R=12/0.4

=120/4

=30 ohm

p.d.2=6v

r=30 ohm

I=v/r

=6/30

=1/5

=0.2 ans

Explanation:

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