Question

6
When a spring is compressed by 2cm, the potential energy stored in it is U. When it
is compressed further by 4cm, the increase in potential energy is
1.40
2. 8U
3. 90
4. 3U
​

Answer 1

Answer:

Abrams Abrasion nji has no clue how to make it

Answer 2

Answer:

(4)The increase in potential energy is 3U.

Explanation:

Given that,

When a spring is compressed by 2cm, the potential energy stored in it is U.

Therefore,

$U=\frac{1}{2}k(2)^{2}=2k\\U=2k-- > (1)$

We are required to find the increase in potential energy if the spring is further compressed by 4cm.

For this condition,$\triangle x=4cm$ and the potential energy of spring is

$U=\frac{1}{2}k(\triangle x)^{2}=\frac{1}{2}k(4)^{2}=8k$

Hence the increase in potential energy is

$\triangle U=8k-2k=6k=3(2k)$

From equation(1),we shall write $\triangle U=3U$

Therefore,

The increase in potential energy is 3U.

#SPJ2