Question

6. Which of the following cannot be the unit digit of a perfect square number?
(a) 6
(b) 1
(c) 9
(d) 8​

Answer 1

Answer:

ʜɪ ᴍᴀᴛᴇ ʜᴇʀᴇ ɪs ᴜʀ ᴀɴsᴡᴇʀ :

Step-by-step explanation:

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UR ANSWER IS

( 8 ) EIGHT 8⃣

BECAUSE NUMBERS ENDING IN 2, 8 , 3 ANS ODD NO OF ZEROS ARE NEVER PERFECT SQUARES

HOPE U GOT IT

PLEASE DO MARK ME AS BRAINLIEST⭐⭐⭐

HAVE A GOOD DAY✌✌

Answer 2

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$\huge\bold{\textsf{\underline{\underline{\pink{QUESTION}}}}}$

➡ Which of the following cannot be the unit digit of a perfect square number?

(a) 6

(b) 1

(c) 9

(d) 8

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$\huge\bold{\textsf{\underline{\underline{\pink{ANSWER}}}}}$

❥ This can be done by eliminating the options out .

→ $\sf {6}^{2}\:=\:3<strong>6</strong>$

→ $\sf {9}^{2}\:=\:8<strong>1 </strong>$

→ $\sf {7}^{2}\:=\:4<strong>9</strong>$

✤ Here , we can see the perfect square can end with 6, 1, 9 but 8 is missing here !

❥ Therefore , the perfect square cannot end with 8 .

${\red\bigstar\large\bold{\mathrm{\underline{\green{Hence, Option\:D\:is\:correct\:i.e.\:8\:.}}}}}$

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