6 Without adding, find the sum. (i) 1+3 + 5 + 7 +9 (ii) 1+3 + 5+7+9+11+13+ 15 + 17 + 19
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Answer:
1)Total consecutive odd numbers = 5
Thus, n = 5
Therefore, sum = n2
= 5 × 5 = 25
2) 1+3+5+7+9+11+13+15+17+19 = 102 = 10×10 =100.
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