Math, asked by sharmakanha708, 4 months ago

6 women and 10 men can finish making pots in 8 hours while 4 women and 6 men finish the same in 12 hours. find work done alone by men and women.
Done this much but the ans isn't coming out right. can anybody plz help ​

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Answered by madhurani2006dp
1

Answer:

48 days

Step-by-step explanation:

Let the work done by 1 man in 1 day = 1/x

Let  the work done by 1 woman in 1 day = 1/y

We are given that 6 men and 10 women can finish making pots in 8 days

So, 6/x + 10/y = 1/8---- A

4 men and 6 women can finish it in 12 days.

So, 4/x + 6/y = 1/12 ---B

Solve A and B

Let 1/x be u and 1/y be v

6u + 10v = 1/8

4u + 6v = 1/12

u=1/48 , v= 0

So, x = 48

So,the time taken by the one man alone from that of one woman alone to finish the work is 48 days

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