Question

6. Write a program to enter 10 no.in an array and replace all
the no: by its reverse. For example if the no.is 57 then it
should be replaced by 75.​

Answer 1

Language:

Python

Program:

a=list(int(input(f"Enter element {i+1}: " )) for i in range(10))  

new=list(( i%10)*10+(i//10) for i in a)

print(new)

Output:

Enter element 1: 10

Enter element 2: 11

Enter element 3: 12

Enter element 4: 13

Enter element 5: 14

Enter element 6: 15

Enter element 7: 16

Enter element 8: 14

Enter element 9: 18

Enter element 10: 78

[1, 11, 21, 31, 41, 51, 61, 41, 81, 87]

Logic:

• For a number in form ab which is expanded as a*10 + b use appropriate operators (// and %)  number ab to get quotient (here a) and remainder (here b) respectively.
• Once you have a and b separated to join them back in use remainder*10 + quotient to get it reversed as ba.

Expand my program:

I tried to make the program as short as possible here's the explanation if you wanna expand it.

• Make 2 empty lists, one to save input 10 numbers and other to save new reversed numbers.
• Get the user input in list one using append method and for loop.
• Use the logic i talked about above to reverse each number from the list one by one and save the numbers in the new list.
• Print the list.

Attachments:

Answer 2

Answer:

My program is based on c++.

#include<iostream.h>

#include<conio.h>

void main()

{

clrscr();

int a[10], i, r=0

cout<<"Enter the elements:-\n";

for(i=0; i<10; i++)

{

cin>>a[i];

}

for(i=0; i<10; i++)

{

r=(r*10)+a[i];

a[i]=r;

}

cout<<"Elements of the array after reverse:\n";

for(i=0; i<10; i++)

{

cout<<a[i];

}

getch();

}

Explanation:

HOPE MY ANSWER HELPS!!!