6. Write the discriminant of quadratic equation: (x + 5)2 = 2 (5x - 3).
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Given :-
(x + 5)² = 2(5x-3)
To find :-
Discriminant of Quadratic equation
Solution:-
First lets simplify the equation
(x + 5)² = 2(5x-3)
In LHS it is in form of (a+b)² = a²+ 2ab + b²
(x + 5)² = 2(5x-3)
x² + 2(x)(5) + (5)² = 10x - 6
x² + 10x + 25 = 10x - 6
Transpose all terms to LHS
x² + 10x + 25 - 10x + 6 = 0
x² + 10x - 10x + 25 + 6 = 0
x² + 0x + 31 = 0
Hence, It is a Quadratic equation
Discriminant of Quadratic equation is b²- 4ac
x² + 0x + 31 = 0
- a = 1
- b = 0
- c = 31
D= (0)² - 4(1)(31)
D = 0- 124
D = -124
Hence Discriminant of (x + 5)² = 2(5x-3) is -124
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Know more :-
Discriminant is denoted by D or Δ
- Discriminant helps to find the nature of roots
Thereare some cases to find the nature of roots
- D=0 Roots are real & equal
- D>0 Roots are Real &Distinct roots
- D<0 Roots are Complex & Conjugate to each other
- D>0 and Perfect square Roots are Rational and Real
- D<0 and not perfect square Roots are Irrational and Real
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