Question

6. Write the following cubes in expanded form:
(1) (2x + 1)
(ii) (20-3b)
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Answer 1

Answer:

(2x+1)^3=(2x)^3+(1)^3+3(2x)(1)(2x+1)

= 8x^3+1+6x(2x+1)

= 8x^3+1+12x^2+6x

= 8x^3+12x^2+6x+1

(20-3b)= (20)^3-(3b)^3-3(20)(3b)(20-3b)

= 8000-27b^3-180b(20-3b)

=8000-27b^3-3600b+540b^2

= -27b^3+540b^2-3600b+8000

Answer 2

Answer:

Hope it helps...........™✌️✌️

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