Math, asked by amitbharti229, 9 months ago

(√6)^x-2=1 solve the given eponential equations

Answers

Answered by Moksh55
2

----------------HEY DEAR----------------------------

HERE IS YOUR ANSWER...

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(1.)(ROOT6) X - 2 = 1

(ROOT6 )X = 3

X = 3/(ROOT6)

X = 3/2.449

X = 1.224......................(ANS.)

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           OR

(2.)IF YOUR QUESTION IS LIKE THIS :

(ROOT 6)^ (X-2) = 1

  WE KNOW IF ANY BASE HAVE POWER 0 THEN IT IS EQUAL TO 1

SO,

(ROOT6)^( X - 2 ) = (ROOT 6)^ 0

COMPARE BOTH EQUATIONS,.......

X-2 =0

X = 2...........................(ANS.)

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HOPE IT HELPS YOU.......

THANKS....

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Answered by Vibes51
18

Answer:

\huge\sf{solution}

\bf{  ( \sqrt{6}  \:  {)}^{x - 2} = 1 } \\

\bf{ (  = {6}^{ \frac{1}{2} }  {)}^{x - 2}   = 1} \\

\bf\pink{ ( {a}^{0}  = 1) } \:  \\ \bf\pink{  {6}^{0}   = 1}

\bf{ = (6 {)}^{ \frac{x - 2}{2} }  = (6 {)}^{0} } \\

\mathtt\purple{bases \: are \: same \: powers \: are \:   } \\ \mathtt\purple{equated}

\bf{  =  \frac{x - 2}{2}   = 0} \\

\bf{ = x - 2 = 0 \times 2  } \\

\bf{  = x - 2 = 0 } \\

\bf{   =  x = 0 - 2} \\

\bf{   therefore \:   \: \: \sf\red{ x = 2}} \:  \:  is \:  answer

Step-by-step explanation:

i hope it helps

#be brainly

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