Question

6.) (x + 2)(x + 3)+(x - 3)(x - 2) - 2x(x + 1) = 0
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Answer 1

Step-by-step explanation:

1. Bring all x together

x+x+x+x+x-2x

2. Shift no. on another side with change in sign:

5x-2x=0-2-3+3+2-1

3x=-1

x=-1/3

=0.333333333

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Answer 2

Hey Mate Here we go

$( x + 2)(x + 3) + (x - 3)(x - 2) - \\ 2x(x + 1) = 0 \\ ({x}^{2} +3x + 2x + 6) + ( {x}^{2}- 2x - 3x - 6) \\ 2 {x}^{2} + 2x = 0 \\ {x}^{2} + 5x + 6 + {x}^{2} - 5x - 6 + 2 {x}^{2} + 2x = 0 \\ 4 {x}^{2} + 2x = 0 \\ 2x(2x + 1) = 0 \\ 2x + 1 = \frac{0}{2x} \\ 2x + 1 = 0 \\ 2x = - 1 \\ x = - \frac{ 1}{2} \\ x = 0.5$

I hope will helps u

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