Question

6/x+2/y=1;4/x-3/y=5​

Answer 1

Answer:

Dividing both side by xy then we have

y6+x3=6;y2+x4=5

Let t=x1andr=y1 equation will be

6r+3t=6;2r+4t=5 on solving we get

t=1r=21

∴x=1andy=2

Answer 2

Step-by-step explanation:

Dividing both side by xy then we have

y

6

+

x

3

=6;

y

2

+

x

4

=5

Let t=

x

1

andr=

y

1

equation will be

6r+3t=6;2r+4t=5 on solving we get

t=1r=

2

1

∴x=1andy=2

(vii)

Let t=

x+y

1

andr=

x−y

1

then equation will be

10t+2r=4;15t−5r=−2 on solving we have

t=

5

1

andr=1

∴x+y=5andx−y=1

Hence, x=4,y=1

(viii)

Let t=

3x+y

1

andr=

3x−y

1

then equation will be

t+r=

4

3

;

2

t

−

2

r

=

8

−1

On solving we have

t=

4

1

andr=

2

1

∴3x+y=4and3x−y=2

Hence, x=1,y=1