Question

6) x + 2y = 3/2; 2x + y =3/2 solve by graphical method

Answer 1

Answer:

The given equation is x−2y=−3 and 2x+y=4

Now, let us find atleast two solutions of each of the above equations, as shown in the following tables.

Table for x−2y=−3 or y= 2x+3

Now, table for 2x+y=4 or y=4−2x

Here, the lines intersecting at point C i.e. (1, 2)

The point which intersect the x axis are B (-3, 0) and E(2, 0)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Solution :

$x + 2y = \frac{3}{2}$

$2x + y = \frac{3}{2}$

Multiplying (i) by 1 and (ii) by 2,

we get,

$x + 2y = \frac{3}{2}$

$4x + 2y = 3$

Subtracting (3) from (4),

we get,

$4x - x + 2y - 2y = 3 - \frac{3}{2}$

$= > 3x = \frac{6 - 3}{2}$

$= > 3x = \frac{3}{2}$

$= > x = \frac{3}{6}$

$= > x = \frac{1}{2}$

Putting x = ½, in equation (4),

we get,

$4 \times \frac{1}{2} + 2y = 3$

$= > 2 + 2y = 3$

$= > 2y = 3 - 2$

$= > y = \frac{1}{2}$

Hence :

The value of x is ½ and the value of y is ½.