Question

6(x+2y)³+8(x+2y)²,?????????!??!!?!!!​

Answer 1

$\bold\pink{\fbox{\sf{Given}}}$

$6(x+2y)^3+8(x+2y)^2$

$\bold\red{\fbox{\sf{To \: Find}}}$

Factorize the given expression

$\bold\green{\fbox{\sf{Solution}}}$

$6(x+2y)^3+8(x+2y)^2$

$2\times (x+2y)(x+2y)(x+2y)+2\times 2\times 2(x+2y)(x+2y)$

Taking $2(x+2y)^2$ common then, we get

$2(x+2y)^2(3(x+2y)+4)$

$2(x+2y)^2(3x+6y+4)$

$2(x+2y)^2(3x+6y+4)$

Hence, the expression factorize as

$2(x+2y)^2(3x+6y+4)$