6( x-3) 2x+1) )^ 4 -5 sqrt x-3 2x+1 +1=0
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4
Answer:
Let 4
√
x
=a and 4
√
x+1
=b.
Thus, a≥0, b≥1, b4−a4=1 and
a+b=4
√
a4+b4
or
(a+b)4=a4+b4
or
2ab(2a2+3ab+2b2)=0,
which gives
ab=0.
Can you end it now.
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