Math, asked by vognesh, 11 months ago

6 X square + 16 X + 48

Answers

Answered by muakanshakya
1
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 {6x}^{2}  + 16x  + 48 = 0 \\  \\as \: we \: know \: that \\  \\ x =  - b  + \sqrt{ {b}^{2}  - 4ac}  \div 2a \\  \\

→. 2(3x^2+8x+24)=0

→. 3x^2+8x+24=0

here ,
a=3, b=8,c=24


x=. -8±√(8)^2-4*3*24/2*3

=. -8+√64-288/6
=. -8+√-224/6

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