6 x square - 3 - 7x
Find zeros of quadratic polynomial
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6x² - 7x - 3 = 0
by mid term splitting method,
6x² - 9x + 2x - 3 = 0
3x(2x - 3) + 1(2x - 3) = 0
(3x + 1)(2x - 3) = 0
if 3x + 1 = 0
x = -1/3
if 2x - 3 = 0
x = 3/2
Answered by
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Answer:
6x^2 -7x-3
= 6x^2 -9x + 2x -3
= 3x( 2x -3) + 1(2x-3)
= (3x +1)(2x -3)
= x = -1÷3 and 3÷2
= the roots are -1÷3 and 3÷2
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