Question

6 x square Y + 9 x y square + 4 y cube

Answer 1

We have:

6$x^{2}y$ + 9$xy^{2}$ + 4$y^{3}$

We have to find, the factorisation of 6$x^{2}y$ + 9$xy^{2}$ + 4$y^{3}$.

Solution:

∴ 6$x^{2}y$ + 9$xy^{2}$ + 4$y^{3}$

Take y as common, we get

= y(6$x^{2}$ + 9xy + 4$y^{2}$)

∴ 6$x^{2}y$ + 9$xy^{2}$ + 4$y^{3}$ = y(6$x^{2}$ + 9xy + 4$y^{2}$)

Thus, the factorisation of 6$x^{2}y$ + 9$xy^{2}$ + 4$y^{3}$ is " y(6$x^{2}$ + 9xy + 4$y^{2}$)".

Answer 2

Answer:

Step-by-step explanation:

6x²y + 9xy² + 4y³

= y ( 6x² + 9xy + 4y²)

To get factorization we have to take y as common.

y ( 6x² + 9xy + 4y²)