Question

6+x-x² find the root​

Answer 1

$\tt\it\bf\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{Solution:-}}}}$

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6+x-x²=0

➨x²-x-6 =0

➨x²+3x-2x-6=0

➨x(x+3) -2(x+3)=0

➨(x+3)(x-2)=0

➨(x+3)=0 or (x-2)=0

➨x⤇-3 or x⤇2

•°• $\tt{\red{ </strong><strong>hence</strong><strong>,</strong><strong>x</strong><strong>=</strong><strong>-</strong><strong>3</strong><strong>\</strong><strong>:</strong><strong>or\</strong><strong>:</strong><strong>2</strong><strong> }}$

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