6-x-x² solve this question in easy methord
Answers
Answered by
17
6-x-x²
=> -1(-6 + x + x²)
=> -(x² + x - 6)
=> -(x² + {3 - 2}x -6)
=> -(x² + 3x - 2x -6)
=> -(x{x+3} -2{x +3})
=> -(x +3)(x-2)
I hope this will help you
-by ABHAY
=> -1(-6 + x + x²)
=> -(x² + x - 6)
=> -(x² + {3 - 2}x -6)
=> -(x² + 3x - 2x -6)
=> -(x{x+3} -2{x +3})
=> -(x +3)(x-2)
I hope this will help you
-by ABHAY
Anonymous:
ryt
Answered by
5
Heya!
Here is yr answer
_____________________________
=> 6 - x - x²
=> - (-6 + x - x² )
Method l:
We need to change the positions of the Values----(quadratic equation rule)
=> - (x² + x -6)
=> - (x² + 3x -2x -6)
=> - [ x (x+3) -2 (x+3) ]
=> - (x+3) (x-2)
x = -3 ------ x = 2
Method ll:
=> - (x² + x -6)
=> - (x² + 3x -2x -6)
=> - [ x² + (3-2)x -6 ]
=> - [ x² + (3+ (-2) )x + (3) (-2) ]
It is in the form of -------
x² + (a+b)x + ab = (x+a) (x+b)
x = x, a =3 , b = -2
=> - (x+3) (x-2)
x = -3 ------- x = 2
Hope it hlpz.....
Here is yr answer
_____________________________
=> 6 - x - x²
=> - (-6 + x - x² )
Method l:
We need to change the positions of the Values----(quadratic equation rule)
=> - (x² + x -6)
=> - (x² + 3x -2x -6)
=> - [ x (x+3) -2 (x+3) ]
=> - (x+3) (x-2)
x = -3 ------ x = 2
Method ll:
=> - (x² + x -6)
=> - (x² + 3x -2x -6)
=> - [ x² + (3-2)x -6 ]
=> - [ x² + (3+ (-2) )x + (3) (-2) ]
It is in the form of -------
x² + (a+b)x + ab = (x+a) (x+b)
x = x, a =3 , b = -2
=> - (x+3) (x-2)
x = -3 ------- x = 2
Hope it hlpz.....
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