Math, asked by pundsanjay01, 5 months ago



(6 y-1) (y-√6)

(√6 y-1) (y+√6)

(√6 y+1)(y+√6)

(√6 y+1)( y-√6)

Answers

Answered by lalitnit
2

Answer:

(6 y-1) (y-√6) \\  = 6 {y}^{2}  - 6 \sqrt{6}y - y +  \sqrt{6}

(√6 y-1) (y+√6) \\  =  \sqrt{6} {y}^{2} + 6y - y +  \sqrt{ 6}

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