Question

6 years ago a man age was 6 times the age of his son. The product of the present age of the father and his son is 396 . What are the their present age ?

Answer 1

Answer:

father's age 36

son's age 11

Step-by-step explanation:

let the present age of father be x

and present age of son be y

product of their ages = 396

x × y = 396

x = 396/y

6 years ago

father age (x-6)

son age (y-6)

x-6 = 6(y-6)

x = 6y-36 + 6

396/y = 6y - 30

dividing above equation by 6

66/y = y - 5

66= y² - 5y

y² - 5y - 66 =0

y² - 11y + 6y - 66 = 0

y (y-11) + 6 (y-11) = 0

(y-11) (y+6) =0

y= 11, -6

so

sons age is 11

and fathers age is 36