Math, asked by aayesha15, 1 year ago

6 years ago A man was three times old as his son in 6 years time he will be twice as old as his son find their present ages

Answers

Answered by himanshuking0654
1
36 year man age
12 year son age

aayesha15: can you solve it and show please
Answered by GamingJAKE
1
present age of the son be X and that of the man b y

first condition

3( x -6) = (y - 6 )

3x-18=y-6

3 x -y - 18 - 6 =0

3x-y = 25.........1

2(x+6)=(y+6)

2x+12=y+6

2x-y =-6.........2

SUBTRACT BOTH EQUATION

3x-y = 25

2x-y =-6

(-) (+) (+)

___________

x =31

present age of man is 31 years

put x = 31 in eq 1
3x-y=25
3(31) - y = 25
93 - 25=y
68= y
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