6 years ago A man was three times old as his son in 6 years time he will be twice as old as his son find their present ages
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36 year man age
12 year son age
12 year son age
aayesha15:
can you solve it and show please
Answered by
1
present age of the son be X and that of the man b y
first condition
3( x -6) = (y - 6 )
3x-18=y-6
3 x -y - 18 - 6 =0
3x-y = 25.........1
2(x+6)=(y+6)
2x+12=y+6
2x-y =-6.........2
SUBTRACT BOTH EQUATION
3x-y = 25
2x-y =-6
(-) (+) (+)
___________
x =31
present age of man is 31 years
put x = 31 in eq 1
3x-y=25
3(31) - y = 25
93 - 25=y
68= y
first condition
3( x -6) = (y - 6 )
3x-18=y-6
3 x -y - 18 - 6 =0
3x-y = 25.........1
2(x+6)=(y+6)
2x+12=y+6
2x-y =-6.........2
SUBTRACT BOTH EQUATION
3x-y = 25
2x-y =-6
(-) (+) (+)
___________
x =31
present age of man is 31 years
put x = 31 in eq 1
3x-y=25
3(31) - y = 25
93 - 25=y
68= y
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