Math, asked by varities1808, 11 months ago

6 years ago a's mother's age (that time) was 2.2 times her age (that time). 4 years hence the respective ratio of their ages (that time) will be 19 : 10. what is the respective ratio of a's present age and her mother's present age ?

Answers

Answered by appoa37f
0
Let the mother age be x +6x
2.2times her age that time
x+2.2+4+x=19.10
2x=19.10-2.2-4
2x=19.10-2.6
2x=16.50
x=8.25
Thus the Present age is 8.25
Answered by ranch0
1
6 years ago -
let a's age = p years
let a's mother's age = q years
q = 2.2p

4 years hence
(q+10) : (p+10) = 19 : 10
(2.2p+10) /(p+10) = 19/10
p = 30
q = 66

present age of a = 36
her mother's present age = 72
respective ratio = 36:72 = 1:2
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