Question

6 years ago a woman had 3 children, and the sum of their ages was was exactly half of her age 5 years ago she had another child Today, the sum of the ages of all the children is exactly equal to her age What is her age today?​

Answer 1

Answer:

40

Step-by-step explanation:

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Answer 2

Answer:

The answer to the given question is 40.

Step-by-step explanation:

Let the present age of the woman be x and s be the sum of first three children.

6 years ago,

s-18 = (1/2)×(x-6)

The present age of the 4th children will be 5.

s+5 = x

After solving the two equations:

x = 40

Therefore present age of the woman is 40.

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