Question

6 years ago aman has 3 children and the sum of their age was exactly half of the man's age 2 years ago he had a 4th child today the sum of the ages of his 4 children is exactly equal to his age. whats is his age today

Answer 1

Answer:

the son is 12 years old.

Explanation:

The red part represents the man, and the white part represents the son. Since the son takes up 1/4 of the shape, and the total area is 48, he takes up 12. Which means the son is 12 years old.

Answer 2

Given

the sum of the age of 3 children was equal to half the age of the man 6 years ago.

4th child was born 2 years ago.

the current age of the nan is equal to the sum of the current age of his children.

To find:

the current age of the man

Solution:

let the present age of the children be A, B, C and D respectively.

since the 4th child is born 2 years ago. then D = 2

let the present age of the man be x

6 years ago.

$(A-6 )+ (B-6) + (C-6 ) = \frac{ x - 6}{2}$

since this equation is for 6 years earlier, 6 is subtracted for each of them .

D is not born yet.

$A-6 + B-6 + C-6 = \frac{x - 6}{2}$

$A + B+ C - 18= \frac{x - 6}{2}$

$A + B + C = \frac{x - 6}{2} + 18$

$A + B + C = \frac{x - 6 + 36}{2}$

$A + B + C = \frac{x + 30}{2}$

let this be equation 1.

now at present

$A + B + C + D = x$

this is the equation for present day.

using equations 1 and D = 2

$\frac{x + 30}{2} + 2 = x$

$\frac{x + 30}{2} - x = - 2$

$\frac{x + 30 - 2x}{2} = - 2$

$- x + 30 = - 4$

$- x = - 4 - 30$

$x = 34$

Therefore, the current age of the man is 34 years.