Question

6 years ago father's age was 11 times that of his son.after 8 years father's age will be 4 times that of his son.find the present age of his son.​

Answer 1

Answer:

Age of son = 12 years

Age of father = 72 years

Step-by-step explanation:

x-6=11(y-6). = x-6=11y-66

= x+60=11y (1)

x+8=4(y+8). = x+8=4y+32

= x-24 =4y (2)

using these two equations we will solve the question

If we will subtract eq.2 from eq.1

We get - 84=7y

thus. y = 12

putting value of y in eq. 2 we get

x-24=4(12)

=. x-24=48

thus ,. x=72