Question

6 years ago, Mahima's mother was 3 times as old as
Mahima. After 5 years, she will be twice as old as Mahima.
Present age (in years) of Mahima's mother is
A) 44
B) 41
P) 39
D) 17​

Answer 1

Given : 6 years ago, Mahima's mother was 3 times as old as Mahima.

After 5 years, she will be twice as old as Mahima.

To Find : Present age (in years) of Mahima's mother is

A) 44

B) 41

P) 39

D) 17​

Solution:

Mahima present age = A

Mahima mother [resent age = B

6 years ago, Mahima's mother was 3 times as old as Mahima.

=> B - 6 = 3(A - 6)

=> B = 3A  - 12

After 5 years, Mahima's mother will be twice as old as Mahima.

=> B + 5 = 2(A + 5)

=> B  = 2A + 5

3A  - 12 = 2A + 5

=> A = 17

B  = 2A + 5 = 2* 17 + 5 = 39

Present age (in years) of Mahima's mother is  39 Years

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Answer 2

SOLUTION

GIVEN

• 6 years ago, Mahima mother age was 3 times as old as Mahima.

• After 5 years, she will be twice as old as Mahima.

TO CHOOSE THE CORRECT OPTION

Present age in years of Mahima mother

A) 44

B) 41

C) 39

D) 17

EVALUATION

Let 6 years ago Mahima's age was x years and Mahima's mother age was 3x years

So present age Mahima = x + 6 years and present age of Mahima's mother = 3x + 6 years

So after 5 years Mahima's age will be x + 11 years and Mahima's mother age will be 3x + 11 years

So by the given condition

$\sf{3x + 11 = 2(x + 11)}$

$\sf{ \implies \: 3x + 11 = 2x + 22}$

$\sf{ \implies \: x = 11}$

Hence present age of Mahima = 17 years and present age of Mahima's mother = 39 years

FINAL ANSWER

Hence the correct option is C) 39

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