Question

6 years ago, mothers age was 6 times her daughters age. three years hence the daughter age would be 1/3 of her mother's age. the current age of mother is?​

Answer 1

Answer:

36 years

Step-by-step explanation:

A woman is three times as old as her daughter.

Let the daughter's present age be x years. Hence the mother’s present age is 3x

Six years ago, the sum of their age was 36.

6 years ago, their ages, daughter's age, x - 6 and mother's age 3x - 6

Sum of their ages 6 years ago

(x - 6) + (3x - 6) = 36

x - 6 + 3x - 6 = 36

4x + (-12) = 36

4x - 12 = 36

4x = 36 + 12

4x = 48

x = 48/4

x = 12

The daughter's present age is 12 years.

The mothers present age 3x = 3 × 12 = 36 years.

Answer : The daughter's present age is 12 years and mothers present age 36 years.

Now Checking the correctness of answer by following the statement

Six years ago their ages, daughters age 12 – 6= 6 years and mothers age 36 – 6=30 years

The sum of their ages, 6 years ago should be 36 years

30 + 6 =36 years.

36 years = 36 years .

Means answer is correct

Answer 2

Step-by-step explanation:

let the present age of mother = x years

let the present age of mother's daughter= y years.

6 years ago,

Age of mother= x-6 years

Age of daughter= y-6 years

So, x-6= 6(y-6)

x-6= 6y-36

x-6y+30= 0

or x-6y = -30 1st equation

3 years hence,

Age of mother= x+3 years

Age of daughter= y+3 years

So, x+3= 1/3(y+3)

x+3= y+3/3

3x+9= y+3

3x-y+6= 0

or 3x-y= -6 2nd equation