Question

6 years ago parul was 8 times as old as nisha 6 years later puruls age is twice as old as nish find their prsent ages

Answer 1

Answer:

Nisha is 8 years

Parul = 22 years

Step-by-step explanation:

Consider the current age of Nisha as x and Parul as y.

Six years ago, their ages will be x-6 and y-6. But we know 6 years ago, Parul’s age was eight times that of Nisha’s.

So their ages 6 years ago will be (x-6) and 8(x-6)

Six year hence, their ages will be x+6 and y+6. But we also know that 6 years hence, Parul’s age will be twice of that of Nisha’s.

So their ages would be (x+6) and 2(x+6)

Parul’s age:

y-6 = 8(x-6)

Eq 1: 8x-y = 42

y+6 = 2(x+6)

Eq 2: 2x-y = -6

Subtract Eq1 and Eq 2

(8x-y)-(2x-y) = 42-(-6)

6x = 48

x = 8. Now we know that Nisha’s present age is 8.

Substitute x = 8 in Eq 2

2(8) - y = -6

y = 16+6 = 22. Parul’s present age is 22

So present ages of Nisha and Parul are 8 and 22

Answer 2

Step-by-step explanation:

Let Parul be P years now and Nisha, N years.

(P-6) = 8(N-6)

P = 8N-48+6 = 8N-42 …(1)

(P+6) = 2(N+6), or

P = 2N+12–6 = 2N+6 …(2)

Equate (1) and (2)

8N-42 = 2N+6, or

6N = 48, or

N = 8 and so P = 22

Nisha is 8 years and Parul, 22 years, now.