Question

( 6 years ago the age of abram is twice , the age of shabnam . if ratio of their present ages 9 : 5 what is the difference between their ages .

Answer 1

Answer:

Age difference between them is 24 years

Explanation:

Given,

6 years ago abram was twice the age of shabnam

If we assume that 6 years ago the age of shabnam was x years.

Then, Abram's age would be 2x years.

So, present age of :-

• Shabnam = (x + 6) years.
• Abram = (2x + 6) years.

According to the question,

Their present age ratio is 9 : 5

∴ (2x + 6) : (x + 6) = 9 : 5

On solving further,

⇒ (2x + 6)/(x + 6) = 9/5

⇒ 5(2x + 6) = 9(x + 6)

⇒ 10x + 30 = 9x + 54

⇒ 10x - 9x = 54 - 30

⇒ x = 24

∴ x = 24

So,

The present age of :-

• Shabnam = (x + 6) = 30 years.
• Abram = (2x + 6) = 54 years.

Hence,

The difference between their ages :-

= 54 - 30

= 24 years.

∴ The difference between their ages is 24 years.

Answer 2

Answer:

let the age of Abram is = X

let the age of shabnam = X

6 years ago the age of Abram is twice than shabnam

so their present age is

Abram = ( 2x + 6 )

Shabnam = ( X + 6 )

the ratio of their age is = 9 : 5

( 2x + 6 ) : ( X + 6 ) = 9 : 5

5 ( 2x + 6 ) = 9 ( X +6 )

10x + 30 = 9x + 54

10x - 9x = 54 - 30

X = 24

so their present age

Abram = 2X + 6

the value of X = 24

Abram =( 2 × 24 + 6 )

Abram = 48 + 6 = 54

Shabnam = ( X + 6 )

shabnam = ( 24 + 6 )

shabnam = 30

Age of Abram = 54

Age of shabnam = 30 .

and their age difference = 54 - 30

= 24 years

hopes it will help you dear