Math, asked by badusha2011kbm, 6 hours ago

6 years back the age of rajuwas 3 times the age of jacob.after 4years the age of raju becomes twice the age of jacob.find the age of two of them now​

Answers

Answered by proboykaustubh
0

Answer:

present Raju age - 36

present Jacob age - 16

Step-by-step explanation:

let Rajus present age be x and Jacobs present age be y

6 years earlier their age would be

(x-6) (y-6)

according to eqn

(x-6)=3(y-6)

x-6=3y-18

x-3y= -18+6

x-3y = -12 (i)

4 yrs later their age would be

(x+4) (y+4)

according to eqn

x+4 = 2(y+4)

x+4 = 2y + 8

x-2y = 8-4

x-2y = 4 -(ii)

subtracting (i) and (ii)

x -3 y = -12

x - 2y = 4

- + -

-y = -16

y= 16

substituting y=16 in (ii)

x - 2(16) = 4

x -32 = 4

x = 36

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