Question

60 = 1/2 × 2x^2 + 3x + 1 find value of x . ​

Answer 1

Step-by-step explanation:

$60 = 1 \div 2 \times {2x}^{2} + 3x + 1 \\ 60 \times 2 = {2x}^{2} + 3x + 1 \\ 120 = {2x}^{2} + 3x + 1 \\ 120 - 1 = {2x}^{2} + 3x \\ 119 = {2x }^{2} + 3x$

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