60×10³ = 0.785 ( 46² - 40² ) × 150
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It is given that the decomposition of A into product has value of k=4.5×103s−1 at 10oC.
log(kK′)=2.303REa[TT′T′−T]
log(4.5×1031.5×104)=2.303×8.31460×103[283T′T′−283]
0.5228=3132.62[283T′T′−283]
T′−283=0.0472T′
T′=297.02 K
T′=297.02K−273=24.02oC
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