Math, asked by shubhamtanty, 2 months ago

60/53of[6/5-{19/5÷(½+⅓)}×15/4]​

Answers

Answered by SaakshiNB
1

Answer:

-18

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Step-by-step explanation:

=\frac{60}{53}*[\frac{6}{5}-[\frac{19}{5}/(\frac{1}{2}+\frac{1}{3})]*\frac{15}{4}]\\\\\\=\frac{60}{53}*[\frac{6}{5}-[\frac{19}{5}/(\frac{3+2}{6})]*\frac{15}{4}]\\\\\\=\frac{60}{53}*[\frac{6}{5}-[\frac{19}{5}/\frac{5}{6}]*\frac{15}{4}]\\\\\\=\frac{60}{53}*[\frac{6}{5}-[\frac{19}{5}*\frac{6}{5}]*\frac{15}{4}]\\\\\\=\frac{60}{53}*[\frac{6}{5}-\frac{114}{25}*\frac{15}{4}]\\\\\\=\frac{60}{53}*[\frac{6}{5}-\frac{57}{5}*\frac{3}{2}]\\\\\\=\frac{60}{53}*[\frac{6}{5}-\frac{171}{10}]\\\\\\

=\frac{60}{53}*[\frac{12}{10}-\frac{171}{10}]\\\\\\=\frac{60}{53}*[\frac{12-171}{10}]\\\\\\=\frac{60}{53}*\frac{-159}{10}\\\\\\=\frac{6}{1}*\frac{-3}{1}\\\\\\=\frac{-18}{1}\\\\\\=-18

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