60-65 4 65-75 5 75-80 6 80-85 8 mean
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Answer:Converting the given data into frequency distribution table
Maths marks No. of students
(f) Cf
60-65 8 8
65-70 12 20
70-75 14 34
75-80 8 42
80-85 5 47
85-90 6 53
90-95 4 57
Σf=57
Here, N=57
Hence the median class =
2
N
=
2
57
=28.5
In the above table 70-75 is the median class and the respective cf is 20 (nearest to the value of 28.5)
Acc to ques, l
1
=70 (lower limit of median class)
CF=20 (C= cumulative frequency preceding the median class)
i=l
2
−l
1
=5 (width of class interval of median class)
f = 14 (frequency of median class)
Median=l
1
+
f
2
N
−C
×i=70+
14
28.5−20
×5
Median= 73.05 (A)
Step-by-step explanation:
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