Question

60. A solid cylinder rolls down a smooth
inclined plane 4.8 m high without
slipping. What is its linear speed at the
foot of the plane, ir it starts rolling from
the top of the plane? (use g = 10 m/s)
(a) 4 m/s
(c) 10 m/s
(b) 2 m/s
fd) 8 m/s​

Answer 1

Answer:

4ms

Explanation:

Because I don't know the answer

Answer 2

Answer:

Hey! here is your required answer stepwise -:

Given is solid cylinder, rolls down without slipping.

for solid cylinder (k2 / R2) = (1/2) where k is radius of gyration also h = 4.8 m

V = √[(2gh) / {1 + (k2 / R2)}]

= √[(2 × 10 × 4.8) / {1 + (1/2)}]

= √(48 × 2 × 2) / 3]

= 8 m/S

Thus,it linear speed is 8 m/S.