60 cm' of oxygen were mixed with 10 cm of a gaseous hydrocarbon, X, CH. After
exploding and cooling to room temperature, 40 cm of gas were left. On shaking with
aqueous sodium hydroxide, 10 cm of oxygen remained. (All measurements were made
at the same temperature) and pressure.
(i)
Calculate the formula of the hydrocarbon, X.
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Let the formula of the hydrocarbon be CxHy. The combustion of the hydrocarbon can be shown as:
CxHy+(x+4y)O2⟶xCO2+2yH2O
The first reduction in volume after the explosion
=10+10(x+4y)−10x=20
=10+410y=20
Thus, y=1010×4=4
The volume of carbon dioxide produced = 20 mI
Thus, 10x=20
⟹x=1020=2
Hence, the molecular formula of the hydrocarbon is C2H4
Therefore, x+y=2+4=6.
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