60.Compute each of the following:
(a)30 + (–25) + (–10)
(b)(–20) + (–5)
(c)70 + (–20) + (–30)
(d)–50 + (–60) + 50
(e)1 + (–2) + (– 3) + (– 4)
(f)0 + (– 5) + (– 2)
(g)0 – (–6) – (+6)
(h)0 – 2 – (–2)
61.If we denote the height of a place above sea level by a positive integer and depth below the sea level by a negative integer, write the following using integers with the appropriate signs:
(a)200 m above sea level
(b)100 m below sea level
(c)10 m above sea level
(d)sea level
62.Write the opposite of each of the following:
(a)Decrease in size
(b)Failure
(c)Profit of Rs.10
(d)1000 A.D.
(e)Rise in water level
(f)60 km south
(g)10 m above the danger mark of river Ganga
(h)20 m below the danger mark of the river Brahmaputra
(i)Winning by a margin of 2000 votes
(j)Depositing Rs.100 in the Bank account
(k)20°C rise in temperature. 63.Temperature of a place at 12:00 noon was +5°C.
Temperature increased by 3°C in first hour and decreased by 1°C in the second hour. What was the temperature at 2:00 pm?
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Answered by
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Answer:
Given that,
Height of a place above sea level is denoted by a positive integer and
Depth below the sea level is denoted by a negative integer
Therefore,
(a) 200 m above sea level =+200
(b) 100 m below sea level =−100
(c) 10 m above sea level =+10
(d) Sea level =0.
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