60 grams of limestone on heating produced 22 grams of carbon dioxide .The percentage of calcium carbonate inot limestone is ?
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answer is48%
Explanation:
48%
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Explanation:
CaCO3 = CaO + CO2
100 g ⇒ 44 g
60 g ⇒ 44 x 60/100 = 26.4 g
60 g of 100% pure limestone would give 26.4 g of CO2
we got only 22 g
So Purity = 22 x 100/26.4
= 83.33%
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