Chemistry, asked by eert861, 9 months ago

60 grams of limestone on heating produced 22 grams of carbon dioxide .The percentage of calcium carbonate inot limestone is ?

Answers

Answered by 0495
0

Answer:

The best

answer is48%

Explanation:

48%

Answered by Anonymous
2

Answer:

Hope it helps you...

Explanation:

CaCO3 = CaO + CO2

100 g ⇒ 44 g

60 g ⇒ 44 x 60/100 = 26.4 g

60 g of 100% pure limestone would give 26.4 g of CO2

we got only 22 g

So Purity = 22 x 100/26.4

                = 83.33%

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