Question

60 Kg of an alloy A is mixed with 100 kg of
alloy B. If alloy A has lead and tin in the ratio
3:2 and alloy B has tin and copper in the ratio
1:4, the amount of tin in the new alloy is.....
​

Answer 1

ratio A is 3:2

tin in A = 2/5 ×60 = 24 kg

tin in B = 1/5 × 100 = 20kg

tin in new alloy = 24 + 20 = 44 kg

Answer 2

The amount of tin is 35% in the new alloy.

Step-by-step explanation:

Since we have given that

Ratio of alloy A = 3 : 2

Ratio of alloy B = 1 :4

Quantity of an alloy A = 60 kg

Quantity of an alloy B = 100 kg

So, According to question, it becomes,

$\dfrac{3}{5}\times 60+\dfrac{1}{5}\times 100:\dfrac{2}{5}\times 60+\dfrac{4}{5}\times 100\\\\=36+20:24+80\\\\=56:104\\\\=28:52\\\\=14:26\\\\=7:13$

The amount of tin in the new alloy would be

$\dfrac{7}{20}\times 100\\\\=7\times 5\\\\=35\%$

Hence, the amount of tin is 35% in the new alloy.

# learn more:

Pure tin alloy was mixed with a 4% tin alloy to produce an alloy that was 16% tin. How much pure tin and how much 4% alloy were used to produce 32 kg of 16% alloy?

https://brainly.com/question/7507877