60 liters of ethane is mixed with 448 liters of pure oxygen at stp if the mixture is ignited and reacts as 2c2h6 + 7o2--> 4co2+6h2o
Calculate volume of co2 formed.
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at stp we know that
one mole is equal to 22.4 liters
60liters is equal to 2.7
448 liters is equal to 20 moles
so eathane is the limiting reagent
2.7 moles of ethane form 5.4 moles
121 liters
one mole is equal to 22.4 liters
60liters is equal to 2.7
448 liters is equal to 20 moles
so eathane is the limiting reagent
2.7 moles of ethane form 5.4 moles
121 liters
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