60%of 1st order reaction was complete in 60min when was it 1/2 half completed
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Firstly find out rate of reaction K using,
K=(2.303/60) * log (100/40)
Now take this k, which come out to be 0.0152 per minute.
For finding time for 50%, you can use any of the 2 approach:
1) you can use the same formual above and substitute the value of k to find time, here log will have different values.
t= (2.303/0.0152)*log(100/50)
t= 45.6 minutes.
2) you can use half life formula for first order reaction.
t=0.693/k
t=0.693/0.0152
t=45.6 minutes.
K=(2.303/60) * log (100/40)
Now take this k, which come out to be 0.0152 per minute.
For finding time for 50%, you can use any of the 2 approach:
1) you can use the same formual above and substitute the value of k to find time, here log will have different values.
t= (2.303/0.0152)*log(100/50)
t= 45.6 minutes.
2) you can use half life formula for first order reaction.
t=0.693/k
t=0.693/0.0152
t=45.6 minutes.
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