Question

60% of magnesium contain 10g of magnesium by mass . how much amount of oxygen will react with 10g of magnesium​

Answer 1

The idea here is that chemical reactions must obey the Law of Mass Conservation, which states that when a chemical reaction takes place, the total mass of the reactants must be equal to the total mass of the products.

In your case, magnesium metal and oxygen gas are the reactants and magnesium oxide is the product.

2

Mg

(

s

)

+

O

2

(

g

)

→

2

MgO

(

s

)

You know that

10.0 g

of magnesium take part in this reaction and that

16.6 g

of magnesium oxide are produced.

You can say that the difference between the mass of the product and the total mass of the reactants, i.e. the mass of magnesium and the mass of oxygen gas, will give you the mass of oxygen gas that took part in the reaction.

m

Mg

+

m

O

2

=

m

MgO

−−−−−−−−−−−−−−−−−−

→

the Law of Mass Conservation

You will thus have

m

O

2

=

m

MgO

−

m

Mg

m

O

2

=

16.6 g

−

10.0 g

=

6.6 g

−−−−

The answer is rounded to one decimal place.

m my friend make me as brainliest and please thanks my 15 answers then I will thanks your answer. ..

Answer 2

Answer:

According to given conditions,

Mass of magnesium=24 g.

Mass of oxide =40 g.

Oxygen combined=40−24=16 g.

16 g of oxygen=24 g magnesium.

∴8 g oxygen=

16

24

×8=12 g.

∴ Equivalent weight of Mg=12 g.

Explanation:

please Thanks my 15 answer