60 passengers are travelling in a bus. some of them are carrying $5 ticket and some are carrying $10 ticket. the total fare received by the conductor is $405.find the number of passengers carrying:
a) $5 ticket
b) $10 ticket
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Answered by
0
Answer:
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Step-by-step explanation:
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Answered by
0
Answer:
Step-by-step explanation:
x*5+(60-x)*10=60(10+5)
=> 5x+600-60x =900
=> 60x-5x = 900-600
=> 55x=300 => x=300/55 = 5.4 => $5= 5.4 => $10= 54.6
Hope it will Help..
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