Math, asked by Wolfaline, 2 months ago

60 pens are divided between Tyson and Tucker in the ratio of 2:3, if the ratio is reversed to 3:2 then how many more pens does Tyson get?

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Answers

Answered by kailashmannem
39

 \huge{\bf{\green{\mathfrak{Question:-}}}}

  • 60 pens are divided between Tyson and Tucker in the ratio of 2:3, if the ratio is reversed to 3:2 then how many more pens does Tyson get?

 \huge {\bf{\orange{\mathfrak{Answer:-}}}}

  •  \textsf{Total number of pens = 60.}

  •  \textsf{Pens are divided between Tyson and Tucker in the ratio 2:3.}

  •  \sf Sum \: of \: the \: Ratio \: = \: 2 \: + \: 3 \: = \: 5.

  •  \sf Tyson\: (pens)\: =

  •  \sf \dfrac{2}{5} \: * \: 60 \:= \: 2 \: * \: 12 \: = \: 24.

  •  \boxed{\sf Tyson \: gets \: 24 \: pens.}

  •  \sf Tucker \: (pens) \: =

  •  \sf \dfrac{3}{5} \: * \: 60 \:= \: 3 \: * \: 12 \: = \: 36.

  •  \boxed{\sf Tucker \: gets \: 36 \: pens.}

  •  \textsf{If the ratios are reversed then,}

  •  \textsf{Number of pens of Tucker will become Tyson and Tyson will become Tucker.}

  •  \textsf{After ratios are reversed, Tyson (pens) = 36 and Tucker (pens) = 24.}

  •  \textsf{Number of pens Tyson will get more =}

  • \sf 36 \: - \: 24

  •  \boxed{\sf 12 \: pens.}

 \huge{\bf{\red{\mathfrak{Conclusion:-}}}}

  •  \boxed{\therefore{\sf Tyson \: gets \: 12 \: more \: pens.}}
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