Math, asked by gallalohith1810, 2 months ago

60 pens are divided between Tyson and Tucker in the ratio of 2:3, if the ratio is reversed to 3:2 then how many more pens does Tyson get? ​

Answers

Answered by Ifell
0

Answer:

12 more pens

Step-by-step explanation:

1 unit: 60÷5

=12

Answered by BrainlyPhantom
6

⇒ Given:

60 pens are divided between Tyson and Tucker in the ratio of 2:3.

The ratio is reversed to 3:2.

⇒ To Find:

The amount of pens Tyson would get more if the ratio is reversed.

⇒ Solution:

The total number of pens = 60

It is divided in the ratio = 2:3

Let the number of pens Tyson and Tucker get be 2x and 3x respectively.

Forming an equation from the given statements:

2x + 3x = 60

5x = 60

\sf{x=\dfrac{60}{5}}

\sf{x=12}

Therefore,

The number of pens Tyson gets = 2x = 2 x 12 = 24 pens

The number of pens Tucker gets = 3x = 3 x 12 = 36 pens

Now, when the ratio is reversed,

Tyson gets 36 pens and Tucker gets 24 pens.

Now, we know that:

The number of pens Tyson gets when the ratio is 2:3 = 24 pens

The number of pens Tyson gets when the ratio is 3:2 = 36 pens

Number of more pens Tyson gets:

\sf{=36-24}

\sf{=12}

∴ Tyson gets 12 extra pens when the ratio is reversed.

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